>if roll[0] > 15:
> .........
>elif roll[0] <=15: <--- this is redundant. already checked for > 15 so if
>here is always <= 15
> if roll[1] >= 2:
>
>you can change with:
>
>elif roll[1] >= 2:
That is not true. The first one looks at index [0], while the second one is
index[1].
>>if roll[0] > 15:
>> if roll[1] >= 2:
>> print("Success")
>> elif roll[2] >= 2:
>> print("Critical failure!")
This will print "Success" if the first roll is greater than 15 AND second roll
is 2 or greater.
It will print "Critical failure!" if the first roll is greater than 15 AND the
second roll is less than 2 AND the third roll is 2 or greater.
Ramit
Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
712 Main Street | Houston, TX 77002
work phone: 713 - 216 - 5423
From: [email protected]
[mailto:[email protected]] On Behalf Of TheIrda
Sent: Friday, August 26, 2011 8:55 AM
To: Christopher King
Cc: python mail list
Subject: Re: [Tutor] Help with if-elif-else structure
Hello,
I'm quite new on python, so don't hit too hard if I'm wrong ;)
A question on the logic... Does this means
if roll[0] > 15:
if roll[1] >= 2:
print("Success")
elif roll[2] >= 2:
print("Critical failure!")
that rolling multiple 1's get the priority on rolling multiple 6's? I mean
result > 15 and 2 1's is always a critical success even if multiple 6 are
rolled?
also
if roll[0] > 15:
.........
elif roll[0] <=15: <--- this is redundant. already checked for > 15 so if here
is always <= 15
if roll[1] >= 2:
you can change with:
elif roll[1] >= 2:
And... which is the RPG name ? :p
Cheers
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