On Mon, Sep 19, 2011 at 1:11 PM, <bod...@googlemail.com> wrote:
> Is there any additional overhead of using the locals() or format(locals())
> instead of a tuple? - the format option is a double function call so I would
> expect that to be considerably slower
>
Using the following code and timeit, it appears that there is a difference,
but unless you call 0.3-6 ns considerable (assuming I got my math correct:
The difference was ~1.2 or ~1.3 seconds for the classic, ~1.9 for the %
locals version, and timeit runs 1,000,000 times with the default settings),
then the difference isn't terrible.
-Wayne
from __future__ import print_function
import timeit
def classicwithlocals():
x = 'hello'
from __future__ import print_function
import timeit
def classicwithlocals():
x = 'hello'
y = 'goodbye'
combined = 'You say %(x)s, and I say %(y)s' % locals()
def classicwithtuple():
x = 'hello'
y = 'goodbye'
combined = 'You say %s, and I say %s' % (x, y)
def withargs():
x = 'hello'
y = 'goodbye'
combined = 'You say {0}, and I say {1}'.format(x, y)
for f in [withargs, classicwithtuple, classicwithlocals]:
t = timeit.Timer(f)
print(t.timeit())
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