On Thu, Sep 29, 2011 at 11:18 PM, Walter Prins <wpr...@gmail.com> wrote:
>
>
> On 29 September 2011 16:13, lina <lina.lastn...@gmail.com> wrote:
>
>> mport os.path
>>
>> tokens=['E']
>> result=[]
>>
>> for fileName in os.listdir("."):
>> if os.path.isfile(fileName) and os.path.splitext(fileName)=="xpm":
>> filedata = open(fileName,'r')
>>
>> text=filedata.readlines()
>> for line in text:
>> print line
>>
>> why here I print nothing out?
>>
>> There is .xpm file there with content.
>>
>> Thanks,
>>
>>
> Is your .xpm files actually text files? Or are they binary (e.g. maybe
> graphics) files? (XPM is normally the extension of a graphics filetype.)
> Treating a binary file as if its text is not liable to work very well.
>
> Also can you please confirm whether this task is homework/study related?
>
I have some awk script to achieve this. I can assure you it's not homework.
LOL ... I have never attended some python course.
sometimes it's hard for you to image how hard I persuade myself to use/think
in python way, forget what is-already-relatively-easy-for-me-to-use bash
script.
the xpm file an read, I just text
f=open('1.xpm','r')
for line in f.readlines():
print line
f.close()
I am google-ing how to get the line index, so will use those after 24.
>
> Walter
>
>
>
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--
Best Regards,
lina
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