Alex Hall wrote:
Hi all,
I have a class which takes a large number of optional arguments for
its __init__. Instead of going through every single one and assigning
it to "self.[name]", is there some quick way to take all the
parameters of the constructor and assign them all to self.[name] in
one step?
If your class takes more than, oh, half a dozen parameters, that is
often Nature's way of telling you the class is badly designed and tries
to do Too Many Things.
But if you really need to:
def __init__(self, **kwargs):
self.__dict__.update(kwargs)
Add your own error checking :)
Also, the above doesn't work with __slots__.
--
Steven
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