On 2011/11/10 09:10 AM, lina wrote:
Hi,
How to remove the coming duplication,
Here I wrote one (not working):
a=['2', '5', '7', '5', '5']
for i in range(len(a)-1):
if a[i+1]==a[i]:
a.remove(a[i+1])
if i not in range(len(a)):
break
a
['2', '7', '5', '5']
I wish to get a is [2,5,7,5]
just remove the coming duplication, not unique the list.
Thanks for any advice,
Best regards,
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def remove_coming_duplication(a_list):
return [element for idx, element in enumerate(a_list) if element !=
a_list[idx-1]]
>>> remove_coming_duplication([2, 5, 7, 5, 5])
[2, 5, 7, 5]
>>> remove_coming_duplication([2, 5, 7, 5, 5, 5, 5, 5, 7, 7, 5])
[2, 5, 7, 5, 7, 5]
>>> remove_coming_duplication(['2', '5', '7', '5', '5'])
['2', '5', '7', '5']
With this you're simply iterating through the list and checking if the
current element in the list is not equal to the previous element, and if
so it is not a duplicate and will be added to the new list you're creating.
--
Christian Witts
Python Developer
//
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