On Tue, Dec 13, 2011 at 10:09 PM, Emile van Sebille <em...@fenx.com> wrote:
> On 12/13/2011 12:39 PM Kaixi Luo said... > > Hello, >> >> I want to create a list of lists of lists (listB) from a list of lists >> (listA). Below there's a snippet of my code: >> >> list1 = [[] for i in range(9)] >> > > Should this be listB? > > > >> # some code here... >> >> listA = [[] for i in range(3)] >> count = 0 >> for i in range(3): >> for j in range(3): >> listB[i].append(listA[count]) >> > > ... if not, where's this come from? > > Emile > > > count+=1 >> >> My question is: is there any alternative way I can initialize listB >> without resorting to using 2 loops? >> >> I'm learning Python coming from a C++ background. So far, I've found >> that Python is an amazingly concise and expressive language. I just want >> to make sure I'm not being badly influenced by my old C++ habits. >> >> Cheers, >> >> Kaixi >> >> >> ______________________________**_________________ >> Tutor maillist - Tutor@python.org >> To unsubscribe or change subscription options: >> http://mail.python.org/**mailman/listinfo/tutor<http://mail.python.org/mailman/listinfo/tutor> >> > > > ______________________________**_________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/**mailman/listinfo/tutor<http://mail.python.org/mailman/listinfo/tutor> > Uh, sorry. I made some very bad typos there. It should be: listA = [[] for i in range(9)] # some code here... listB = [[] for i in range(3)] count = 0 for i in range(3): for j in range(3): listB[i].append(listA[count]) count+=1 Kaixi
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