On 13/01/12 10:56, Nick W wrote:
first problem: easy fix just remember that len() returns the actual
number of items in the list but that list is indexed starting at 0 so
just replace your line of
pick = len(names)
with:
pick = len(names) - 1
Another good trick for choosing a random value from a list is to avoid picking
a number first and just ask for a random choice:
>>> import random
>>> L = ['spam', 'ham', 'cheese', 'eggs']
>>> random.choice(L)
'cheese'
and for problem #2:
just use string formating... like for example instead of:
print (names[win_number], " is the winner!")
try something along the lines of:
print("{} is a winner".format(names[win_number]))
Apart from being longer and harder, is there an advantage to the second form?
:)
A third alternative is:
print("%s is a winner" % names[win_number])
In any case, none of these solve the actual problem. The original poster is
talking about printing the list of names:
print (names, "have been entered.")
which prints an actual LIST, so you get (e.g.):
['fred', 'barney']
instead of:
fred barney
The easy way to fix that is to use:
print (" ".join(names), "have been entered.")
--
Steven
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