Shreesh bhat wrote:
*Lucky Numbers*
A number is called lucky if the sum of its digits, as well as the sum of
the squares of its digits is a prime number. How many numbers between A and
B are lucky?
Very little of this is relevant to your problem. In the future, please provide
a short, self-contained, correct example that demonstrates the problem.
http://sscce.org/
Here is the shortest example I can see, a single line of code:
xrange(2**31-1, 2**31)
which gives the same error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
OverflowError: long int too large to convert to int
(The error message itself can vary from version to version.)
Possible solutions:
* Don't use xrange, write your own generator which will do the job.
def my_xrange(start, stop):
i = start
while i < stop:
yield i
i += 1
This will work, but will be much slower.
* Scale your numbers from time to time, to avoid them getting too big.
* Can you rethink your algorithm and avoid needing such huge numbers?
* Just accept that your function can't handle such huge numbers.
Traceback (most recent call last): File
"/run-1327085301-1965755690/solution.py",
line 35, in li=map(islucky,xrange(startnum, endnum))
OverflowError: Python int too large to convert to C long
-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
It shows this error for very large numbers or slows down with large numbers.
It slows down for large numbers because you have written a very inefficient
isprime() function.
I m using Ubuntu 32-bit.
What is more important than the version of your operating system is the
version of Python.
On Sun, Jan 22, 2012 at 4:24 AM, <tutor-requ...@python.org> wrote:
[snip hundreds of irrelevant lines]
Please do not reply to digest posts without deleting the unnecessary quoting,
and setting the subject line appropriately.
You may find it useful to read this:
http://catb.org/esr/faqs/smart-questions.html
--
Steven
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