> import numpy as np >> Vhel_fdiff3 = np.array([abs(Vmatch3_1 - Vmatch3_2), abs(Vmatch3_1 - >> Vmatch3_3), abs(Vmatch3_3 - Vmatch3_2)]) >> your_answer = Vhel_fdiff3.max(axis=0) > > or > > import numpy as np > a = np.array([Vmatch3_1-Vmatch3_2, Vmatch3_1-Vmatch3_3, Vmatch3_3- > Vmatch3_2]) > print np.max(np.abs(a), axis=0)
yes, this one is better than mine. It is more flexible, leaving more options for what you may want to do with it afterwards, andre _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
