On 14 April 2012 18:29, Bod Soutar <bod...@googlemail.com> wrote: > > > On 14 April 2012 16:27, Tom Tucker <tktuc...@gmail.com> wrote: > >> >> Hello all. Any suggestions how I could easily iterate over a list and >> print the output 3 across (when possible)? One method I was considering >> was removing the recently printed item from the list, checking list length, >> etc. Based on the remaining length of the list I would then print X >> across. Yah? Is their and easier approach I might be overlooking? >> >> >> For example... >> >> mylist = ['serverA', 'serverB', 'serverC', 'serverD',' serverE', >> 'serverF', 'serverG'] >> >> >> Desired Output >> ============ >> serverA serverB serverC >> serverD serverE serverF >> serverG >> >> _______________________________________________ >> Tutor maillist - Tutor@python.org >> To unsubscribe or change subscription options: >> http://mail.python.org/mailman/listinfo/tutor >> >> > How about something like this > > > mylist = ['serverA', 'serverB', 'serverC', 'serverD','serverE', > 'serverF', 'serverG'] > tempstr = "" > count = 0 > > for item in mylist: > count += 1 > if count == 3: > tempstr += (i + "\n") > count = 0 > else: > tempstr += (i + " ") > > print tempstr > > > The above code prepares an empty string variable, and a count variable. On > each iteration, it checks to see if the count is equal to 3. If it is, then > it appends the current list element to the string and also adds a newline > character("\n"), then the count is reset to 0. If the count isn't 3, it > simply appends the current list element along with a space. > > Hope this helps, > Bodsda > > > erm, I screwed up my variable names. where you see 'i', this should be item (or the other way around). My bad.
-- Bodsda
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