Thanks. That makes sense, just failed to notice it. Btw, I tried printing
out wordDict and Python became unresponsive. Any ideas
On Wed, Jun 27, 2012 at 8:33 PM, Dave Angel <d...@davea.name> wrote:
> On 06/27/2012 08:19 PM, moheem ilyas wrote:
> > I am working on a problem from a book, Think Python, which I thought
> would
> > be fairly easy. The problem is:
> >
> > Exercise 11.1. Write a function that reads the words in words.txt and
> > stores them as keys in a
> > dictionary. It doesn’t matter what the values are. Then you can use the
> in
> > operator as a fast way to
> > check whether a string is in the dictionary.
> >
> > Note: words.txt is just a huge word list file if anyone is confused about
> > that
> >
> > Here is my failed solution:
> >
> > def tester():
> > fin = open('/home/moheem/Documents/words.txt', 'r')
> > value = 0
> > wordDict = dict()
> > for word in fin:
> > wordDict[word] = value
> > value = value + 1
> >
> > fin.close()
> >
> > There seems to be a logical error. That is, when I check a key, i.e. one
> of
> > the words from the file, is in the dictionary, I get false. (To check, I
> > use: 'aa' in wordDict). I think the problem is that the key does not
> > actually get placed in the dictionary, but the question is why?
> >
> >
>
> Somehow you're thinking that the file consists only of words, and that
> the for loop you've got will give you those words one at a time. It
> doesn't.
>
> When you loop on a file that way, the lines each end in a newline
> character, so you've got to strip them off before using them as keys.
>
> for word in fin:
> word = word.rstrip()
> wordDict[word] = value
> value += 1
>
> You could have discovered this by simply printing out wordDict
>
>
>
>
>
> --
>
> DaveA
>
>
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