Il 28/07/2012 17:12, Francesco Loffredo ha scritto:
ok, as usual when I look again at something I wrote, I found some little mistakes. Here's my errata corrige:Il 19/07/2012 19:33, PyProg PyProg ha scritto:I had to study carefully your present and desired lists, and I understood what follows (please, next time explain !): - each 7-tuple in your present list is a record for some measure relative to a person. Its fields are as follows:Hi all,I would get a new list as: [(0, '3eA', 'Dupont', 'Juliette', '11.0/10.0', '4.0/5.0', '17.5/30.0', '3.0/5.0', '4.5/10.0', '35.5/60.0'), (1, '3eA', 'Pop', 'Iggy', '12.0/10.0', '3.5/5.0', '11.5/30.0', '4.0/5.0', '5.5/10.0', '7.5/10.0', '40.5/60.0')] ... from this one: [(0, '3eA', 'Dupont', 'Juliette', 0, 11.0, 10.0), (0, '3eA', 'Dupont', 'Juliette', 1, 4.0, 5.0), (0, '3eA', 'Dupont', 'Juliette', 2, 17.5, 30.0), (0, '3eA', 'Dupont', 'Juliette', 3, 3.0, 5.0), (0, '3eA', 'Dupont', 'Juliette', 4, 4.5, 10.0), (0, '3eA', 'Dupont', 'Juliette', 5, 35.5, 60.0), (1, '3eA', 'Pop', 'Iggy', 0, 12.0, 10.0), (1, '3eA', 'Pop', 'Iggy', 1, 3.5, 5.0), (1, '3eA', 'Pop', 'Iggy', 2, 11.5, 30.0), (1, '3eA', 'Pop', 'Iggy', 3, 4.0, 5.0), (1, '3eA', 'Pop', 'Iggy', 4, 5.5, 10.0), (1, '3eA', 'Pop', 'Iggy', 5, 40.5, 60.0)] How to make that ? I'm looking for but for now I can't do it. Thanks in advance. a+- field 0: code (I think you want that in growing order)- field 1: group code (could be a class or a group to which both of your example persons belong)- fields 2, 3: surname and name of the person- field 4: progressive number of the measure (these are in order already, but I think you want to enforce this) that you want to exclude from the output list while keeping the order - field 5, 6: numerator and denominator of a ratio that is the measure. you want the ratio to be written as a single string: "%s/%s" % field5, field6Taking for granted this structure and my educated guesses about what you didn't tell us, here's my solution:def flatten(inlist) """ takes PyProg PyProg's current list and returns his/her desired one,given my guesses about the structure of inlist and the desired result.""" tempdict = {} for item in inlist: if len(item) != 7: print "Item errato: \n", item id = tuple(item[:4]) progr = item[4] payload = "%s/%s" % item[5:] if id in tempdict: tempdict[id].extend([(progr, payload)]) else: tempdict[id] = [(progr, payload)] for item in tempdict:tempdict[item].sort() # so we set payloads in progressive order, if they aren't already# print "Temporary Dict: ", tempdict tmplist2 = [] for item in tempdict: templist = [] templist.extend(item) templist.extend(tempdict[item]) tmplist2.append(tuple(templist)) tmplist2.sort()# so we set IDs in order # print "Temporary List: ", tmplist2 outlist = [] for item in tmplist2: templist = [] if isinstance(item, tuple): for subitem in item: if isinstance(subitem, tuple): templist.append(subitem[1]) else: templist.append(subitem) outlist.append(tuple(templist)) else: outlist.append(item) # print "\nOutput List: ", outlist return outlist
1- of course, a function definition must end with a colon...
line 1:
def flatten(inlist):
2- sorry, English is not my first language...
line 9:
print "Item length wrong!\n", item
3- I didn't insert a break statement after line 9, but if inlist
contained a wrong item it would be nice to do something more than simply
tell the user, for example we could skip that item, or trim / pad it, or
stop the execution, or raise an exception... I just told it to the
unsuspecting user, and this may very probably lead to some exception in
a later point, or (much worse) to wrong results. So:
line 8-9:
if len(item) != 7:
print "Item length wrong!\n", item
raise ValueError("item length != 7")
... now I feel better ... but I must avoid reading my function again, or
I'll find some more bugs!
Francesco _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
