Hi, Is it intended behavior that regular expression flags are ignored when compiled regexes are used? In the code below, I intend to match path names case-independently, but once the flags (in this case: no flags at all) have been set in re.compile, subsequent flags in re.search are ignored (no pun intended). This is sneaky! Is this because of the old Python version I am using? Python 2.5.1 (r251:54863, Apr 18 2007, 08:51:08) [MSC v.1310 32 bit (Intel)] on win32 >>> import re >>> s = r"""DATA LIST FILE = >>> '\\besh1f\inkomen3\iis1\iistaak\produktie\dividend\base\j2010\bestand\D1305_01' >>> /""" >>> regex = "(file|name) ?= ?['\"]([^'\"]+)['\"]" >>> m1 = re.search(regex, s, re.I) >>> m1.group(2) '\\\\besh1f\\inkomen3\\iis1\\iistaak\\produktie\\dividend\\base\\j2010\\bestand\\D1305_01' >>> compiledRegex = re.compile(regex, s) ## no ignorecase here >>> m2 = re.search(compiledRegex, s, re.I) ## re.I (ignorecase) is SILENTLY >>> IGNORED >>> m2 is None True
Thanks in advance for your replies! Regards, Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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