On Thu, Oct 04, 2012 at 05:26:13PM -0400, eryksun wrote: > On Thu, Oct 4, 2012 at 4:04 PM, Joel Goldstick <joel.goldst...@gmail.com> > wrote: > > > >>>> my_string = "123" > >>>> pad = 8 - len(my_string) % 8 > >>>> my_string = my_string + " " * pad > >>>> my_string > > '123 ' > > If len(my_string) is already a multiple of 8, the above sets pad to 8: > > >>> s = "12345678" > >>> pad = 8 - len(my_string) % 8 > >>> pad > 8
Here's another way: py> from __future__ import division py> from math import ceil py> "%*s" % (int(ceil(len(mystring)/8)*8), mystring) ' 123412341234' Or left-justified: py> "%-*s" % (int(ceil(len(mystring)/8)*8), mystring) '123412341234 ' In Python 3, there is no need for the "from __future__" line. -- Steven _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
