On Sun, Dec 9, 2012 at 4:48 AM, Peter Otten <__pete...@web.de> wrote: > >>>> def interleave(items, separator): > ... for item in items: > ... yield item > ... yield separator > ...
+1 for this solution if a generator function is desired. It only requires basic Python syntax and performs well. I still prefer itertools.chain/repeat if it's for a one-off expression. >>>> def interleave(items, separator): > ... result = 2 * len(items) * [separator] > ... result[::2] = items > ... return result This is fast if a list will do. The question asks for a tuple, though. Including the time to build a tuple makes this approach a bit slower than the first one. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
