On Wed, Feb 6, 2013 at 9:44 PM, Mara Kelly <schooluse1...@yahoo.com> wrote:
> Hi everyone, trying to write a program that has the user enter a password,
> checks if it contains any vowels, and if it does prints ' It is false that
> password(whatever the user enters) has no vowels,' and if it has no vowels
> prints it is True that password has no vowels...
>
> Here is what I have so far...
> def password(y):
> vowels=["a","e","i","o"]
> if y[0] in vowels:
> return False
> if len(y) ==0:
> return True
> elif(y[len(y)-1] != vowels):
> return False
> else:
> return password(y[1:len(y)-1])
> x=input("Enter a password:")
> print("It is", password(x),"that",x,"has no vowles")
>
> As of now it just asks for the password, and then prints 'It is False that
> password(whatever was entered) has no vowles' for any word I enter. I think
> maybe some of my if statement conditions may be being returned to the
> function, but then not printing the appropriate one? Can anyone help?
> Thanks!
>
It appears that the issue is from this:
elif(y[len(y)-1] != vowels):
This condition will be true because you are comparing a string with a list.
Thus causing passwrod() returning False.
>
> _______________________________________________
> Tutor maillist - Tutor@python.org
> To unsubscribe or change subscription options:
> http://mail.python.org/mailman/listinfo/tutor
>
>
--
Regards,
YeeYaa (Simon Yan)
http://simonyan.fedorapeople.org/
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
