Hi guys, I wondered if you knew what I could add to this code so that when the
user enters 1 from the menu and then doesn't enter a valid binary number the
program should ask them over and over again until valid binary number is
entered.
here is the code:
def show_menu():
print("=======================")
print("1-binary to denary")
print("2-denary to binary")
print("3-exit")
print("=======================")
while True:
show_menu()
choice = input("please enter an option: ")
if choice == '1':
binary = input("Please enter a binary number: ")
denary = 0
place_value = 1
for i in binary [::-1]:
denary += place_value * int(i)
place_value *= 2
print("The result is",denary)
elif choice == '2':
denary2 = int(input("Please enter a denary number: "))
remainder = ''
while denary2 > 0:
remainder = str(denary2 % 2) + remainder
denary2 >>= 1
print("The result is",remainder)
elif choice == '3':
break
elif choice not in '1' or '2' or '3':
print("Invalid input-try again!")
Thanks
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