On 22/03/13 12:39, Mitya Sirenef wrote:
You can do it with groupby like so:from itertools import groupby from operator import itemgetter maxDate = "2013-03-21" mmax = list() obs.sort(key=itemgetter('date')) for k, group in groupby(obs, key=itemgetter('date')): group = [dob for dob in group if dob['realtime_start'] <= maxDate] if group: group.sort(key=itemgetter('realtime_start')) mmax.append(group[-1]) pprint.pprint(mmax)
This suffers from the same problem of finding six records instead of one, and that four of the six have start dates before the given date instead of after it. Here's another solution that finds all the records that start on or after the given data (the poorly named "maxDate") and displays them sorted by date. selected = [rec for rec in obs if rec['realtime_start'] >= maxDate] selected.sort(key=lambda rec: rec['date']) print selected -- Steven _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
