I forgot about update. It's nice and clean:
a.update(b)
However, when 'a' has values and 'b' is None, the 'a' item gets clobbered with
None. I found this on stackoverflow.com:
------------------
old = {1: 'one', 2: 'two'}
new = {1: 'newone', 2: None, 3: 'new'}
old.update( (k,v) for k,v in new.iteritems() if v is not None)
------------------
Exactly what I need.
Thanks for the update hint!
Ken
On Tue Apr 2 2:50 , Dave Angel sent:
>On 04/01/2013 10:28 PM, ke...@kendy.org wrote:
>> You guys are awesome! You make it look easy and I learn every time.
>>
>
>Once you've got the two dicts, take a look into the update method. It
>may make any loops unnecessary, except for debugging.
>
>
>--
>DaveA
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