Hi all,
I'm having a doubt in the below program's 2n'd "for" loop.
>>> for n in range(2, 10):
... for x in range(2, n):
... if n % x == 0:
... print n, 'equals', x, '*', n/x
... break
... else:
... # loop fell through without finding a factor
... print n, 'is a prime number'
...
2 is a prime number
3 is a prime number
4 equals 2 * 2
5 is a prime number
6 equals 2 * 3
7 is a prime number
8 equals 2 * 4
9 equals 3 * 3
My doubt is that "will 'x' be always of value 2, if so why that for loop
"for x in range(2, n):"
i don't know how the first output , as If 2%2==0:(this satisfies the if
loop as x =2) , so how the else part came to output i.e 2 is a prime number.
Please educate me in this.
Thanks in advance,
-Bessen
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