On 23/10/2013 22:12, Jackie Canales wrote:
> let say i have a file with random letters of A, AB, C, CD, AC, A, D, CD, DD,
> C, B, AB, CD, AB
> How do i count the occurrence of each individual item.
>
> def occurence(name):
> infile = open('bloodtype1.txt', 'r')
> lst = infile.read()
read() doesn't return a list, it returns a string. So the name is
poorly chosen. Probably you wanted a list, with each item containing
one or two letters.
You can use split(",") to break the string into a list, based on commas.
And you can use strip() on each item of that list to get rid of
whitespace.
> infile.close()
>
> print(lst.count('AB')) # 3
> print(lst.count('CD')) # 2
> print(lst.count('DD'))# 1
>
>
> i know i can do lst.count("AB") it will give me 3 but if i were to do
> lst.count("A") it would give me 6 what I am having trouble with is just
> getting the occurrence of the A by itself to give me 1 since there is just
> one occurrence of it and would need to do the same for c and d with out it
> counting the them in the occurrence of AC and DD or CD.
When searching the original string, you have that problem. Making an
actual list will fix it.
--
DaveA
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