On 10/30/2013 1:08 PM, Peter O'Doherty wrote:
Hi List,
I know a geometric sequence can be produced by:
series = [2**x for x in range(7)]
But I would like to curtail the sequence before the last element
excedes a certain value.
import itertools
series = [2**x for x in itertools.takewhile(lambda x: 2**x<60, range(7))]
if the limit is really large you could calculate it once:
import itertools
import math
limit = int(math.log(60)) + 1
series = [2**x for x in itertools.takewhile(lambda x:x<limit, range(7))]
which in turn leads to:
import math
series = [2**x for x in range(int(math.log(60)) + 2)]
--
Bob Gailer
919-636-4239
Chapel Hill NC
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