On 2014-01-04 18:44, Danny Yoo wrote:
Hi Alex,
According to:
http://www.hostip.info/use.html
there is a JSON-based interface. I'd recommend using that one! JSON
is a format that's easy for machines to decode. The format you're
parsing is primarily for humans, and who knows if that will change in
the future to make it easier to read?
Not only is JSON probably more reliable to parse, but the code itself
should be fairly straightforward. For example:
#########################################################
## In Python 2.7
##
import json
import urllib
response = urllib.urlopen('http://api.hostip.info/get_json.php')
info = json.load(response)
info
{u'country_name': u'UNITED STATES', u'city': u'Mountain View, CA',
u'country_code': u'US', u'ip': u'216.239.45.81'}
#########################################################
This strikes me as being the most elegant solution to date, and I thank
you for it!
The problem is that the city name doesn't come in:
alex@x301:~/Python/Parse$ cat tutor.py
#!/usr/bin/env python
# -*- coding : utf -8 -*-
# file: 'tutor.py'
"""
Put your docstring here.
"""
print "Running 'tutor.py'......."
import json
import urllib
response = urllib.urlopen\
('http://api.hostip.info/get_json.php?ip=201.234.178.62&position=true')
info = json.load(response)
print info
alex@x301:~/Python/Parse$ ./tutor.py
Running 'tutor.py'.......
{u'city': None, u'ip': u'201.234.178.62', u'lat': u'10.4',
u'country_code': u'CO', u'country_name': u'COLOMBIA', u'lng':
u'-75.2833'}
If I use my own IP the city comes in fine so there must still be some
problem with the encoding.
should I be using
encoding = response.headers.getparam('charset')
in there somewhere?
Any ideas?
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