On Feb 23, 2014, at 2:26 AM, Peter Otten <__pete...@web.de> wrote:
> which still shows a repetetive pattern and thus you can simplify it with
> another loop. You should be able to find a way to write that loop with two
> star_row() calls on a single iteration, but can you do it with a single call
> too?
So, I was able to cut it down a bit but I’m having a hard time trying to cut it
down with another loop and a single call. Wouldn’t what you’re saying in the
above paragraph have to be another function with a loop inside? Or are you
saying just another loop will suffice? Any hints? Here is what I got so far,
I’ll put the loop in question in bold.
from turtle import *
from math import sin, sqrt, radians
def star(width):
R = (width)/(2*sin(radians(72)))
A = (2*width)/(3+sqrt(5))
penup()
left(18)
penup()
forward(R)
pendown()
left(162)
forward(A)
right(72)
forward(A)
left(144)
forward(A)
right(72)
forward(A)
left(144)
forward(A)
right(72)
forward(A)
left(144)
forward(A)
right(72)
forward(A)
left(144)
forward(A)
right(72)
forward(A)
penup()
left(162)
forward(R)
left(162)
showturtle()
def fillstar(color):
fillcolor(color)
begin_fill()
star(25)
end_fill()
red = "red"
fillstar(red)
def space(width):
penup()
forward(2*width)
pendown()
space(25)
def row(width):
penup()
right(90)
forward(width)
right(90)
forward(11*width)
right(180)
pendown()
def star_row(numberstars):
for i in range (numberstars):
fillstar(red)
space(25)
star_row(5)
row(25)
star_row(5)
row(25)
star_row(6)
row(25)
star_row(5)
row(25)
star_row(6)
row(25)
star_row(5)
row(25)
star_row(6)
row(25)
star_row(5)
row(25)
star_row(6)
This is what I’m thinking…
for I in range(4)
star_row(5)
row(25)
star_row(6)
row(25)
???? Am I at all close?
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