On 24/02/2014 16:36, Peter Otten wrote:
Bob Williams wrote:
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My operating system is Linux (openSUSE 13.1).
I'm trying to create symlinks. The following code:
if pathList[j][-3:] == "mp3":
linkName1 = pathList[j][0:-3] + "mp3"
linkName2 = destPath + linkName1[len(sourcePath):]
print 'Creating link %s -> %s' % (linkName2, pathList[j])
os.symlink(pathList[j], linkName2)
fails with this error:
Creating link /pollux/music/portable/testing/artists/Death in
June/1995 Rose Clouds Of Holocaust/10 Lifebooks.mp3 ->
/home/bob/music/artists/Death in June/1995 Rose Clouds Of Holocaust/10
Lifebooks.mp3
Traceback (most recent call last):
File "/home/bob/Documents/scripts/python/flac2mp3.py", line 101, in
<module>
os.symlink(pathList[j], linkName2)
OSError: [Errno 2] No such file or directory
The same thing happens in ipython, when I type the paths in manually.
I have tried escaping the spaces with '\', but the same error is
generated.
The file "/home/bob/music/artists/Death in June/1995 Rose Clouds Of
Holocaust/10 Lifebooks.mp3" definitely exists.
Thanks,
os.symlink(existing_file, symlink_to_create)
fails with that error if the directory that shall contain the new symlink
does not exist. You can create it before making the symlink with
try:
os.makedirs(os.path.dirname(symlink_to_create))
except OSError as err:
# Assume the directory exists.
# A thorough coder would check the errno here
pass
Python 3.3+ allows finer grained error handling than that shown above,
so you could catch FileExistsError, see
http://legacy.python.org/dev/peps/pep-3151/ for the details.
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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