street.swee...@mailworks.org Wrote in message:
> I'm trying to sort the order of elements in an xml file, mostly
> to make visual inspection/comparison easier. The example xml and
> code on http://effbot.org/zone/element-sort.htm get me almost
> what I need, but the xml I'm working with has the element I'm
> trying to sort on one level deeper.
>
>
> That page's example xml:
>
> <phonebook>
> <entries>
> <entry>
> <name>Ned</name>
> <number>555-8904</number>
> </entry>
> <entry>
> <name>John</name>
> <number>555-5782</number>
> </entry>
> <entry>
> <name>Julius</name>
> <number>555-3642</number>
> </entry>
> </entries>
> </phonebook>
>
>
> And that page's last example of code:
>
> import xml.etree.ElementTree as ET
> tree = ET.parse("data.xml")
> def getkey(elem):
> return elem.findtext("number")
> container = tree.find("entries")
> container[:] = sorted(container,key=getkey)
That would be more clearly written
sort(container,key=getkey)
> tree.write("new-data.xml")
>
>
......
> Traceback (most recent call last):
> File "./xmlSort.py", line 16, in <module>
> container[:] = sorted(container, key=getkey)
> TypeError: 'NoneType' object is not iterable
>
That simply tells you that tree.find () returns None.
>
> "container[:] = sorted(container, key=getkey)" confuses me,
> particularly because I don't see how the elem parameter is passed
> to the getkey function.
>
You should play with a list, sorting it with a key function. For
example make a list of strings, using a key=
def mykey (elem):
return elem.lower ()
To see what's going on, add a print to that function, showing
yourself that the sort function will call mykey () on each
element.
I can't help with the xml stuff, but it seems clear you have to
produce a find call that gives you the right list.
--
DaveA
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