Scott W Dunning <scott....@cox.net> Wrote in message: > Iâm working on a few exercises and Iâm a little stuck on this one. > > This is what the book has but it just gives me an endless loop. > > def square_root(a, eps=1e-6): > while True: > print x > y = (x + a/x) / 2 > if abs(y-x) < epsilon: > break >
Without an initial value for x, this should give an immediate exception. Assuming you fix that as below, you now have the problem that they never change x, so if it isn't right on first loop, it never will be. Next you have the problem of inconsistent spelling of eps. And final thing I notice is that it doesn't return a value. Once you remove the debug print in the function, there's no way to see the result. > round(square_root(9)) > > I tweaked Good job, you fixed most of the bugs. > it to what I thought was correct but when I test it I get nothing back. > > def square_root(a, eps=1e-6): > x = a/2.0 > while True: > y = (x + a/x)/2.0 > if abs(x - y) < eps: > return y > x = y > > round(square_root(9)) > > The way I tweaked it seems to work, Iâm getting the correct answer on the > calculator but the interpreter is not returning anything when I check in > python. Sure it is, you're just not printing it. You forgot to save the result of rounding, and forgot to print the saved value. -- DaveA
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