Hi Danny,
I followed your suggestion.
Tomorrow morning I will run this new version of the code.
Now using a sample of 81 elements (instead of 600000) the profile returns:
Thu Apr 10 23:25:59 2014 restats
18101188 function calls in 1218.626 seconds
Ordered by: internal time
List reduced from 13 to 10 due to restriction <10>
ncalls tottime percall cumtime percall filename:lineno(function)
1 1015.803 1015.803 1218.334 1218.334 skymaps5.py:44(mymain)
18101000 202.490 0.000 202.490 0.000 {method 'write' of 'file'
objects}
1 0.292 0.292 1218.626 1218.626 <string>:1(<module>)
6 0.029 0.005 0.029 0.005 {open}
5 0.010 0.002 0.010 0.002 {method 'close' of 'file'
objects}
81 0.002 0.000 0.002 0.000 {method 'split' of 'str'
objects}
82 0.001 0.000 0.001 0.000 {zip}
1 0.000 0.000 0.000 0.000 function_base.py:8(linspace)
1 0.000 0.000 0.000 0.000 function_base.py:93(logspace)
5 0.000 0.000 0.000 0.000 {numpy.core.multiarray.zeros}
Anyway I would like to try to speed it up using C functions (and maybe
comparing the resuts of the two profile in the end)
How can I do it now? Can I use Cython?
Thanks
Gabriele
2014-04-10 21:38 GMT-04:00 Danny Yoo <d...@hashcollision.org>:
> > Comment: You are looping over your sliced eel five times. Do you
> > need to? I like eel salad a great deal, as well, but, how about:
> >
> >
> > for k in eel:
> > MYMAP1[i, j, k] = MYMAP1[i, j, k] + myinternet[oo]
> > MYMAP2[i, j, k] = MYMAP2[i, j, k] + myinternet[oo]
> > MYMAP3[i, j, k] = MYMAP3[i, j, k] + myinternet[oo]
> > MYMAP4[i, j, k] = MYMAP4[i, j, k] + myinternet[oo]
> > MYMAP5[i, j, k] = MYMAP5[i, j, k] + myinternet[oo]
> > oo = oo + 1
>
>
> Hi Gabriele,
>
> Also note that, when Martin looked at this part of the code, he
> unfortunately misinterpreted its effect; Martin's proposed rewrite
> here does not preserve the meaning of the original code. But rather
> than wag my finger at how Martin interpreted the code, I'd rather make
> the observation that this is a warning sign that the original code
> here was not easy to understand.
>
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