On 23/05/2014 13:23, Felipe Melo wrote:
Hello,
I want to read the below matrix, identify when the characters in front
of "want = " are equal to "1" and then save in an array and in an output
file the characters above. But I don't know how to identify the second
line and store in a variable:
alpha=0 beta=2 gamma=50
want = 0
alpha=0 beta=2 gamma=50
want = 1
alpha=0 beta=2 gamma=50
want = 0
alpha=0 beta=2 gamma=50
want = 1
alpha=0 beta=2 gamma=50
want = 0
This is part of the code:
try:
datadir = '/home/me/Test_python/'
fileHandle = open( "%s/teste.txt"%datadir, 'r'
)
vector = [ ]
for line in fileHandle.readlines():
line=line.strip()
a = line.split(" ")[0]
print a
b = line.split(" ")[1]
print b
c = line.split(" ")[2]
print c
d = line.split(" ")[3]
print d
if d == "1":
vector.append([a,b,c])
n = n + 1
fileHandle.close()
file = open("saida.txt","w")
for cont in range(n):
file.write = vector
except:
print "Exception"
sys.exit( 1 )
When I execute the code there is an error when the loop finds the second
line
[felipe@grumari Test_python]$ python verificar.py
alpha=0
beta=2
gamma=50
Exception
You've made a classic newbie mistake by catching all exceptions. Take
the try/except out of your code and Python will tell you precisely where
your problem actually is. Try this and if you can't make any progress
please get back to us. You also only need one call to line.split, not
four, and I'm unsure whather or not the call to vector.append is what
you actually want.
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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