On 24/06/2014 22:01, mark murphy wrote:
Hi Danny, Marc, Peter and Alex,
Thanks for the responses! Very much appreciated.
I will take these pointers and see what I can pull together.
Thanks again to all of you for taking the time to help!
Cheers,
Mark
On Tue, Jun 24, 2014 at 4:39 PM, Danny Yoo <[email protected]
<mailto:[email protected]>> wrote:
The sorting approach sounds reasonable. We might even couple it with
itertools.groupby() to get the consecutive grouping done for us.
https://docs.python.org/2/library/itertools.html#itertools.groupby
For example, the following demonstrates that there's a lot that the
library will do for us that should apply directly to Mark's problem:
#########################################
import itertools
import random
def firstTwoLetters(s): return s[:2]
grouped = itertools.groupby(
sorted(open('/usr/share/dict/words')),
key=firstTwoLetters)
for k, g in grouped:
print k, list(g)[:5]
#########################################
In order to really overwhelm you see more_itertools.pairwise here
http://pythonhosted.org//more-itertools/api.html as I've found it useful
on several occasions.
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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