On 11/07/2014 12:27, Avishek Mondal wrote:
Hi,
I wrote a simple program, as follows-
def finddivisor(n1, n2):
divisor = ()
What's wrong with divisor = [] # a list
for i in range(1, min(n1+n2)+1):
if n1%i == 0 and n2%i==0:
divisor = divisor + (i, )
Then divisor.append(i)
return divisor
n1 = eval(input('Enter first number: '))
n2 = eval(input('Enter second number: '))
Please don't use the code above.
n1 = int(input('Enter first number: '))
divisors= finddivisor(n1,n2)
print (divisors)
However, when I run it, the message
Traceback (most recent call last):
File "C:/Python33/Trials/tuple trial.py", line 21, in <module>
divisors= finddivisor(n1,n2)
File "C:/Python33/Trials/tuple trial.py", line 12, in finddivisor
for i in range(1, min(n1+n2)+1):
TypeError: 'int' object is not iterable
shows up. Could you please tell me where I went wrong? Does it mean that
if i in an integer, it will not be iterated? But isn't the code for i in
range(1, n) a very frequently used line?
It is indeed, but not when you've mistyped it :) Take a close look at
your call to min()
Thank you for your help!
Not at all.
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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