jarod...@libero.it wrote:
> Hin there!!!
>
> I have a niave question on dictionary analysis:
> If you have a dictionary like this:
> diz
> Out[8]: {'elenour': 1, 'frank': 1, 'jack': 1, 'ralph': 1}
>
> and you have a list and you want to know which keys are not present on my
> dictionary the code are simple.
> for i in diz.keys():
> ...: if i in mitico:
> ...: print "NO"
> ...: else:
> ...: print i
> ...:
> NO
>
> But I havethis problem I have a file and I want to know which elements are
> not present on my file from dictionary.
> more data.tmp
> jack 1
> pippo 1
> luis 1
> frate 1
> livio 1
> frank 1
>
>
> with open("data.tmp") as p:
> for i in p:
> lines= i.strip("\n").split("\t")
> if not diz.has_key(lines[0]):
> ....: print i
> ....:
> pippo 1
>
> luis 1
>
> frate 1
>
> livio 1
>
> The output I want is to have :
> ralph and 'elenour.. how can I do this?
> thanks in advance!
You have the logic backwards. You have to iterate over the names in the dict
and look them up in the file:
>>> diz = {'elenour': 1, 'frank': 1, 'jack': 1, 'ralph': 1}
>>> def find_name(name):
... with open("data.tmp") as f:
... for line in f:
... if name == line.split("\t")[0]:
... return True
... return False
...
>>> for name in diz:
... if not find_name(name):
... print name
...
ralph
elenour
However, this is very inefficient as you have to read the file len(diz)
times. It is better to store the names in a data structure suited for fast
lookup first and then to use that instead of the file. Python's dict and set
types are such data structures, so as we don't care about an associated
value let's use a set:
>>> with open("data.tmp") as f:
... names_in_file = {line.split("\t")[0] for line in f}
...
>>> for name in diz:
... if not name in names_in_file:
... print name
...
ralph
elenour
Digging a bit deeper you'll find that you can get these names with set
arithmetic:
>>> set(diz) - names_in_file
set(['ralph', 'elenour'])
or even:
>>> diz.viewkeys() - names_in_file
set(['elenour', 'ralph'])
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