On 05/09/14 22:32, Crush wrote:
count = 0
while count < 3:
count += 1
Subprocess.Popen('command')
This is not real code since 'command' is presumably
not the real command and subprocess is not spelled with an 'S'...
Its usually better to post real code.
if count == 3:
sys.exit()
This does not work as I want it to;
No, it does what you asked it to.
Computers cannot guess your intentions, they
only do what you tell them.
I only want it to execute once. However, if there is an error, I want it to try
again,
but only if count does not equal 3.
Let's translate that to Python
count = 1
error = subprocess.Popen('command') # execute once
while error and count < 3: # if error and less than 3
error = subprocess.call('command') # on success call() returns zero
count += 1
> If count equals 3, i want it to give up and exit or do something else.
else:
raise SystemExit # or something else
Is that the sort of thing?
PS
If you really must use Popen then detecting the error condition is
slightly more work: You need to explicitly assign the Popen object's
returncode value to error.
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos
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