Felisha Lawrence wrote:
> I have the following program
> import os
>
> path = '/Users/felishalawrence/testswps/vol1'
> for file in os.listdir(path):
> newFile = path+file[:file.rindex("v")]+"v20"
>
> print newFile
> and I want to output the results of the 'newFile' variable into the
> directory specified by the 'path' variable. There are current files in
> this directory, but I would like tho replace them with different names.
> Can anyone point me in the right direction?
So you can no longer defer that dreadful task? ;)
To rename a file you need its old and its new name, both preferrably with
their complete path, for example
for old_name in os.listdir(path):
old_file = os.path.join(path, old_name)
new_name = old_name[:old_name.rindex("v")] + "v20"
new_file = os.path.join(path, new_name)
os.rename(old_file, new_file)
If there are only files containing a "v" in your
/Users/felishalawrence/testswps/vol1 folder
the above should already work. Here are a few ideas to make it more robust
(or rather less brittle):
Verify that old_name contains a "v" using the `in` operator
Verify that old_file is a file using os.path.isfile()
Verify that new_file doesn't exist with os.path.exists()
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