I am not certain that my terminology is correct in the subject line. Let me explain my issue.
Scenario A: 1) I start out inside a commercial software environment (Abbreviated CSA henceforth). 2) I initiate a script in the CSA's scripting language. 3) This script calls an external Python script.com 4) This Python script generates a Tkinter window, populating it with information from the CSA. 5) Control will not pass back to the CSA until the Tkinter window is closed. Because of this, none of the CSA's tools can be used until the Tkinter window is closed. Scenario B: 1) I start out inside the CSA. 2) I initiate a script in the CSA's scripting language. 3) This script calls an external Python script in a new thread. 4) This Python script generates a Tkinter window, populating it with information from the CSA. 5) Control returns to the CSA while the Tkinter window is populating itself. The CSA's tools can be used while the Tkinter window remains open displaying its information. My users want scenario B to occur. This way they can refer to the Tkinter window's info and make changes to their plan based on this info. However! Once they make their changes they will want to rerun the same Python script. This would then result in TWO Tkinter windows being open, one displaying the old info, the new one with the post-changes info. This is not acceptable. So, how do I: 1) Check for the existence of an already open window from a previous running of the script? 2) If such a window exists, how do I close it from the new script execution? And, then, of course generate a new instance of the information window. I need to be able to identify the existence of such a window without causing anything to happen to the CSA's normally open windows. And then close the particular window I need closed -- IF it is even open. I feel the solution must be in Tkinter's access to the X Window system, but nothing in the documentation is *clicking* with me yet. Thanks! -- boB _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
