On 20/10/15 12:29, Vusa Moyo wrote:
Hi there. My script is as follows,
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
# Add your function below!
def average(numbers):
> total = sum(numbers)
> total = float(total)
That line isn't necessary since the inputs are floats already.
> total = total / len(numbers)
> return total
>
def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
return 0.1 * homework + 0.3 * quizzes + 0.6 * tests
def get_letter_grade(score):
if score >= 90:
return "A"
elif score >= 80:
return "B"
print get_average(lloyd)
def get_class_average(students):
results = []
for a in students:
b = int(get_average(a))
results.append([b])
return results
get_class_average(alice)
I receive a zero value for results, which doesnt quite make sense to me.
Nor to me. Are you sure its a zero result? It should be a list of some
kind not a number. Or do you mean you get an empty list back?
Notice that get_class_average() expects your students value to be
some kind of sequence or collection. The for loop will iterate over
that. If you pass Alice as a single student it will iterate over the
keys, trying first of all to get the average of "Alice" which should
fail with an error. Did you get any errors? If so please let us see them.
Please show us the actual code you execute, the actual output
and the full text of any errors.
One other thing that seems weird to me is that you go to great pains to
produce a float as a result of get_average() but then you
immediately convert it to an int. Why not leave it as a float?
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog on Flickr at:
http://www.flickr.com/photos/alangauldphotos
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