On 19/11/15 15:31, Greg Christian wrote:
I’m trying to sort a list of tuples based on the second item in the tuple. When
I run this in IDLE I get the correct output; however, when running inside of a
program, and calling the counter() function, sorted does not seem to work? Any
ideas on why this works in IDLE and not in program would be appreciated. Thank
You.
def getKey(item):
return item[1]
def counter():
L = [("baby", 9999), ("aeuron", 100), ("pablo", 1234)]
sorted(L, key=getKey)
print ("L = ", L)
OUTPUTS THIS (when calling counter inside of program):
L = [('baby', 9999), ('aeuron', 100), ('pablo', 1234)]
sorted() returns the soirted collection, it does not sort it in place.
If you want in-place use the sort method.
OUTPUTS THIS (when running with IDLE – desired output):
[('aeuron', 100), ('pablo', 1234), ('baby', 9999)]
I'm not sure why IDLE does that.
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog on Flickr at:
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