dear pythonistas
i have written the code below for identifying tuples occurring twice or more
times in the list of tuples called "flights".
1. Question: How can i modify this code so it does not matter which string is
first and which is second or (h,i) == (i,h) respectively ?
2. Question: On my python file I have written the rather long list of tuples in
3 lines. If I break them down in multiple shorter lines
the for loop will not work through the last tuple.
Thanks in advance for help, Marcus.
>>> lst = dict()
>>> a = 'M1'
>>> b = 'M2'
>>> c = 'M3'
>>> d = 'M4'
>>> e = 'M5'
>>> f = 'M6'
>>> g = 'M7'
>>> h = 'M8'
>>> i = 'M9'
>>> j = 'M10'
>>> k = 'M11'
>>> l = 'M12'
>>> flights = (h,i), (h,j),(k,f), (k,a), (f,a), (e,f), (e,g), (d,g),
>>> (l,c),(l,b), (c,b),(j,c), (j,k), (c,k), (h,f), (h,d), (f,d), (a,l),
>>> (a,g),(e,i), (e,b,), (i,b), (i,l), (i,k), (l,k), (f,j),(f,b),
(j,b),(h,a),(h,g),(a,g),
(d,e), (d,c), (e,c), (i,c), (i,d), (c,d), (f,e,),(f,i),(e,i), (a,j,),
(a,b), (j,b), (h,l), (h,k), (l,k), (l,f),
(l,g),(f,g),(b,k), (b,d), (k,d), (i,a), (i,j), (a,j), (h,c), (h,e),
(c,e), (h,j)
>>> for pair in flights:
if pair not in lst:
lst[pair] = 1
else:
lst [pair] += 1
>>> for key,val in lst.items():
if val > 1:
>>> print key, val
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