Is there a way to extend the numbers so that there is no more L? Thanks :)
On Tue, Dec 22, 2015 at 8:29 PM, Alan Gauld <alan.ga...@btinternet.com> wrote: > On 22/12/15 10:05, Satya Luzy wrote: > > I'm currently making a cryptanalysis program that involves up to 150 > > integer digits. > > The number will be used for multiplication and exponentiation purpose. > > So, do I need to use something like a big integer class? or does that > even > > exist? > > Python integers are effectively big integers, no need of a special > class. Just use normal integers. > > If in doubt try this (using Python v2): > > >>> print 2 ** 500 > 327339060789614187001318969682759915221664204604306 > 478948329136809613379640467455488327009232590415715 > 0886684127560071009217256545885393053328527589376L > > Notice the L at the end? That tells you python is using a > long integer. You only see that in Python v2. If you are > using v3 there is no L and no distinction between long > and regular integers. > > -- > Alan G > Author of the Learn to Program web site > http://www.alan-g.me.uk/ > http://www.amazon.com/author/alan_gauld > Follow my photo-blog on Flickr at: > http://www.flickr.com/photos/alangauldphotos > > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > https://mail.python.org/mailman/listinfo/tutor > _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
