On 2016-01-11 04:51, Rene Werner wrote:
Hello list,
right now I am working on a couple of programming-related challenges.
The
challenges are sorted into problem sets, where each set contains a
number
of problems.
Because a lot of these problems rely on code that is often the same, I
have
put these parts into a seperate file, util.py, and I simply do
from util import *
in each solution. I have my solutions organized in different folders,
one
for each problem set:
set1/prob1.py
set1/prob2.py
set2/prob3.py
and so on. So far, I keep symlinking util.py in each set folder, so
e.g.
set1/util.py is a symlink to ../util.py. The same goes for set2, set3
and
so on. This works, but I get the feeling that it is clumsy and could be
done better.
What is the usual way in python do realize this in a way so that I
don't
have to symlink util.py for every problem set, but still have it
available?
Thank you very much for your time.
Kind regards
M.M.
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I used to do it with symlinks as well but what I do now I believe
is the preferred way.
I have all my Python work under a ~/Py directory (in my /home/alex
folder)
For each project I create a subfolder there: ~/Py/CurrentProject, or
~/Py/CP for short.
Under ~/Py/CP you can put all your other code organized in what ever way
suits you best.
The CP directory and every directory under it should contain an empty
file called __init__.py.
For example:
~/Py/CP
__init__.py
src
__init__.py
main.py
tests
__init__.py
test.py
test.py can import main.py with the following import statement:
import CP.src.main as main
as long as ~/Py is in your PYTHONPATH environment variable.
This can be set dynamically in your code but I do it by having the
following in my ~/.bashrc file:
export PYTHONPATH="${PYTHONPATH:+$PYTHONPATH:}/home/alex/Py"
I'm submitting this not because I am an expert, but because this is the
way I've learned to do it from postings on this list (for which I would
like again to express gratitude) and would be interested in hearing if I
got it right. So in a sense, it is a question rather than an answer.
ak
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