On 02/03/17 13:42, Rafael Knuth wrote:
> bar = ["beer", "coke", "wine"]
>
> customer_order = input("What would you like to drink, dear guest? ")
>
> for drink in bar:
> if customer_order != drink:
> print ("Sorry, we don't serve %s." % customer_order)
> else:
> print ("Sure, your %s will be served in a minute!" % customer_order)
>
> What I want the program to do is to "silently" loop through the list
So you only want the sorry... message if the loop completes without
finding a drink. That means you need to put that print statement after
the loop. Python includes a feature for that - a for/else construct.
for drink in bar:
if drink == customer_order:
print(Sure...)
break #exit loop and avoid else
else:
# only if the loop completes normally
However, there is another way to do this that doesn't
use an explicit loop: the 'in' operator
if customer_order in bar:
print("sure....)
else:
print ("Sorry....)
hth
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
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