I’ve improved it a bit to meet the following conditions:
1. type(base) == int and exponent == 0
2. base == 0 < exponent
3. (base > 0 or base < 0) and exponent > 0
4. base > 0 > exponent
5. base < 0 > exponent
6. base == 0 > exponent
def power(base, exponent):
if type(base) == int and exponent == 0:
return 1
elif base == 0 < exponent:
return 0
elif (base > 0 or base < 0) and exponent > 0:
result = base
for _ in range(1, exponent):
result *= base
return result
elif base > 0 > exponent:
exponent = -(exponent)
result = base
for _ in range(1, exponent):
result *= base
return 1 / result
elif base < 0 > exponent:
exponent = -exponent
result = base
for _ in range(1, exponent):
result *= base
return 1 / result
elif base == 0 > exponent:
print('0 cannot be raised to a negative power.')
#Testing first condition
print(power(0, 0))
print(power(-1, 0))
print(power(1, 0))
#Testing second condition
print(power(0, 3))
#Testing third condition
print(power(2, 3))
print(power(-2, 3))
#Testing fourth condition
print(power(2, -3))
#Testing fifth condition
print(power(-2, -3))
#Testing sixth condition
print(power(0, -3))
I don’t know if it’s anywhere near built-in pow() function, but your reply
made me think about all those conditions and try to see if I can make my
previous function code a little better. I need your feedback please.
Sri
On Sun, Mar 5, 2017 at 7:37 AM, Alex Kleider <aklei...@sonic.net> wrote:
> On 2017-03-04 08:17, Sri Kavi wrote:
>
> I'm a beginner learning to program with Python. I'm trying to explain a
>> solution in plain English. Please correct me if I'm wrong.
>>
>
> Create a function that takes base and exponent as arguments.
>>
>
> Is seems that you are facing the same problem as Tasha Burman.
> Sounds like an assignment meant to exercise your use of iteration.
> i.e. ** and various built in power functions that have been suggested are
> out of bounds.
>
> In the body of the function:
>> set a result variable to the base.
>>
>
> def pwr(base, exponent):
> ....
> res = base
> ...
>
>> User a for-loop with a range of 1 to the exponent.
>>
>
> for i in range(begin, end): # The challenge is to pick begin and end.
>
> end will be a function of exponent but not exponent itself.
> I don't think 1 is a good choice for begin.
> Picking the correct begin is related to dealing with the following:
>
> What if any of the following are true, and what should be done in each
> case?
> if exponent ==1: .....
> if exponent = 0: .....
> if exponent < 0: .....
> Each of the first two might deserve its own return statement.
>
>
>> With each iteration, set the result to the product of result times base.
>>
>
> res *= base # same as res = res * base
>
>
> It's a fun little exercise- a bit more complex than I initially thought it
> would be.
>
> Please share your implementation.
>
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