On Fri, Apr 14, 2017 at 11:59:25PM +0530, shubham goyal wrote: > sorted(ls) > sorted(ls1)
Here you sort ls and throw the result away, then you do the same to ls1. sorted() makes a copy of the list and sorts it. You need to write: ls = sorted(ls) ls1 = sorted(ls1) but even better would be to sort in place: ls.sort() ls1.sort() which doesn't make a copy. -- Steve _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
