On 15/04/17 03:17, Palm Tree wrote: > s="2*3+3(8-4(5+6+9))+2+3+3(4/4)" > > i want to find expression enclosed in brackets. > > i want outputs to be like: > (8-4(5+6+9)) > (5+6+9) > (4/4) >
You probably could do it with some fancy regex but personally I'd investigate a proper text parser. There is a module to support that in the standard library but I can't recall its name, however you need a bit of background in parsing to use it. Google(or bing or...) is your friend. If you really want to do it manually you need to count the brackets going in and then back out. So as you scan your sample data the counter will go 0,1,2,1,0,1,0 If you store those counts along with the string index where they change you can use that to slice your string accordingly. Its all a bit messy but should work... -- Alan G Author of the Learn to Program web site http://www.alan-g.me.uk/ http://www.amazon.com/author/alan_gauld Follow my photo-blog on Flickr at: http://www.flickr.com/photos/alangauldphotos _______________________________________________ Tutor maillist - [email protected] To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
