Alan Gauld via Tutor wrote: > On 20/04/18 05:53, D.V.N.Sarma డి.వి.ఎన్.శర్మ wrote: >> I have a situation in which the same code gives an error in idle but >> works in qtconsole >> regards, >> >> *in idle* >> v = np.zeros(len(x)) >> >> for i in range(len(x)): >> if x[i] < 1.0: >> v[i] = 0 > > You don't give us any clue to what x (or V) is, > so its hard to know what is going on.
The code may be the same, but it's probably not fed the same data. I'm guessing that x is a numpy array. The code above produces an error if the array has more than one dimension: $ python3 Python 3.4.3 (default, Nov 28 2017, 16:41:13) [GCC 4.8.4] on linux Type "help", "copyright", "credits" or "license" for more information. >>> import numpy >>> x = numpy.array([1,2,3]) >>> for i in range(len(x)): ... if x[i] < 1.0: pass ... >>> x = numpy.array([[1,2,3], [4,5,6]]) >>> for i in range(len(x)): ... if x[i] < 1.0: pass ... Traceback (most recent call last): File "<stdin>", line 2, in <module> ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() Comparing an array with a scalar uses broadcasting to build another array >>> numpy.array([1,2,3]) < 3 array([ True, True, False], dtype=bool) and the numpy developers forbid using an array in a boolean context because it's not clear what bool(some_array) is supposed to return. Instead you have to make explicit if you want all values or at least one value to be truthy. > Also how are you running the code in IDLE? > Are you running the same file using the Run > menu option? Or are you importing your module? > > Also which Python version are you using? _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
