I've noticed the same thing, and if I've got firebug open, I see an error referring to jQuery not being defined.
On Mar 3, 9:54 am, Jerry Thompson <jerrycando...@gmail.com> wrote: > Just noticed that the Twitter's Tweet button which opens up a popup > window for sharing, upon posting to Twitter, there's a link to "Return > to X site". Clicking this link will open the originating site within > the JS popup. Shouldn't it simply just close the popup window as the > user is already on the originating site? -- Twitter developer documentation and resources: http://dev.twitter.com/doc API updates via Twitter: http://twitter.com/twitterapi Issues/Enhancements Tracker: http://code.google.com/p/twitter-api/issues/list Change your membership to this group: http://groups.google.com/group/twitter-development-talk
