I've noticed the same thing, and if I've got firebug open, I see an
error referring to jQuery not being defined.

On Mar 3, 9:54 am, Jerry Thompson <jerrycando...@gmail.com> wrote:
> Just noticed that the Twitter's Tweet button which opens up a popup
> window for sharing, upon posting to Twitter, there's a link to "Return
> to X site".  Clicking this link will open the originating site within
> the JS popup.  Shouldn't it simply just close the popup window as the
> user is already on the originating site?

Twitter developer documentation and resources: http://dev.twitter.com/doc
API updates via Twitter: http://twitter.com/twitterapi
Issues/Enhancements Tracker: http://code.google.com/p/twitter-api/issues/list
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