Hello Mikhail,
On 26/08/2025 at 02:48:29 +03, Mikhail Kshevetskiy
<mikhail.kshevets...@iopsys.eu> wrote:
> The shown speed inverse linearly depends on size of data.
> See the output:
>
> spi-nand: spi_nand nand@0: Micron SPI NAND was found.
> spi-nand: spi_nand nand@0: 256 MiB, block size: 128 KiB, page size: 2048,
> OOB size: 128
> ...
> => mtd read.benchmark spi-nand0 $loadaddr 0 0x40000
> Reading 262144 byte(s) (128 page(s)) at offset 0x00000000
> Read speed: 63kiB/s
> => mtd read.benchmark spi-nand0 $loadaddr 0 0x20000
> Reading 131072 byte(s) (64 page(s)) at offset 0x00000000
> Read speed: 127kiB/s
> => mtd read.benchmark spi-nand0 $loadaddr 0 0x10000
> Reading 65536 byte(s) (32 page(s)) at offset 0x00000000
> Read speed: 254kiB/s
>
> In the spi-nand case 'io_op.len' is not the same as 'len',
> thus we divide a size of the single block on total time.
> This is wrong, we should divide on the time for a single
> block.
>
> Signed-off-by: Mikhail Kshevetskiy <mikhail.kshevets...@iopsys.eu>
Happy to see this is useful :-) But you're totally right, it didn't use
the correct length. Maybe I would rephrase a bit the last two sentences
to make the commit clearer:
"In the spi-nand case 'io_op.len' is not always the same as 'len', thus
we are using the wrong amount of data to derive the speed."
However, regarding the diff,
> @@ -594,9 +594,10 @@ static int do_mtd_io(struct cmd_tbl *cmdtp, int flag,
> int argc,
>
> if (benchmark && bench_start) {
> bench_end = timer_get_us();
> + block_time = (bench_end - bench_start) / (len / io_op.len);
> printf("%s speed: %lukiB/s\n",
> read ? "Read" : "Write",
> - ((io_op.len * 1000000) / (bench_end - bench_start)) /
> 1024);
> + ((io_op.len * 1000000) / block_time) / 1024);
Why not just dividing the length by the benchmark time instead of
reducing and rounding the denominator in the first place, which I
believe makes the final result less precise?
Thanks,
Miquèl
