Jerry Van Baren wrote:
> So you should be able to use
>    0xE0800000..0xE0FFFFFF - 2nd "copy" of the first bank
>    0xE1000000..0xE17FFFFF - 1st "copy" of the second bank
> you will double your available consecutive memory.  You can do the same 
> thing with the third and fourth banks of memory, but you will still have 
> a gap between the first pair and second pair.  This will reduce your 
> four fragments / three holes to two fragments / one hole.  Solved half 
> your problem anyway.
>    0xE4800000..0xE4FFFFFF - 2nd "copy" of the first bank
>    0xE5000000..0xE57FFFFF - 1st "copy" of the second bank
doh!                                            ^^^^^^

s/first/third/
s/second/fourth/

Sorry for the cut&paste error.
gvb

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