Dear Mike Frysinger,
In message <[email protected]> you wrote:
>
> > > > +if [ ! -z "$ARCH" -a "$ARCH" != "$2" ]; then
> > >
> > > is the !-z really needed ?
> >
> > We don't want the check to trigger if ARCH is not defined.
> > [ "$ARCH" != "$2" ] will trigger as "" != "arm"
>
> the implied question is whether this is a valid state. i know you dont wan>
> t
> that kind of comparison, but i thought the Makefile would have set it up fo>
> r
> you by default. now that i think about it a bit more, that isnt what happe>
> ns
> at all.
>
> so only thing to change here is to use -n and not !-z
Or even omit the (redundant) "-n" and just write
if [ "$ARCH" -a "$ARCH" != "$2" ]; then
...
Best regards,
Wolfgang Denk
--
DENX Software Engineering GmbH, MD: Wolfgang Denk & Detlev Zundel
HRB 165235 Munich, Office: Kirchenstr.5, D-82194 Groebenzell, Germany
Phone: (+49)-8142-66989-10 Fax: (+49)-8142-66989-80 Email: [email protected]
Use the Force, Luke.
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