If the logbuffer contains LOGBUFF_LEN chars, they never got
printed with the "log show" command, because chars get
printed with the following for loop:
for (i = 0; i < (size & LOGBUFF_MASK); i++) {
with size = LOGBUFF_LEN and LOGBUFF_MASK = (LOGBUFF_LEN-1)
for loop never executed ...
Fix this.
Signed-off-by: Heiko Schocher <h...@denx.de>
---
common/cmd_log.c | 4 +++-
1 files changed, 3 insertions(+), 1 deletions(-)
diff --git a/common/cmd_log.c b/common/cmd_log.c
index ff5924c..b98a091 100644
--- a/common/cmd_log.c
+++ b/common/cmd_log.c
@@ -220,7 +220,9 @@ int do_log(cmd_tbl_t *cmdtp, int flag, int argc, char *
const argv[])
start = log->v1.start;
size = log->v1.size;
}
- for (i = 0; i < (size & LOGBUFF_MASK); i++) {
+ if (size > LOGBUFF_LEN)
+ size = LOGBUFF_LEN;
+ for (i = 0; i < size; i++) {
s = lbuf + ((start + i) & LOGBUFF_MASK);
putc(*s);
}
--
1.7.7.6
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